5x^2-93x-140=0

Solution for 5x^2-93x-140=0 equation:

5x^2-93x-140=0

a = 5; b = -93; c = -140;
Δ = b2-4ac
Δ = -932-4·5·(-140)
Δ = 11449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11449}=107$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-93)-107}{2*5}=\frac{-14}{10}
=-1+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-93)+107}{2*5}=\frac{200}{10}
=20
$